If is given that radium decomposes at a rate proportional to the amount present. If `p %` of th original amount of radium disappears in `l` years, what percentageof it will remain after `2l` years?

If is given that radium decomposes at a rate proportional to the amount present.If po of th original amount of radium disappears in l years,what percentageof it will remain after 2l years?

Radium decomposes at the rate proportional to the amount present at any time. If p percent of amount disappears in one year, what percent of amount of radium will be left after 2 years?

If radium decoposes at a rate proportional to tha amount Q present, then the differential equation is

Experiments show that radium decomposes at a rate proportioanl to the amount of radium present at the moment. If its half life is 1570 years, what percentage will disappear in one years?

A radioactive substance disintegrates at as rate proportional to the amount of substance present. If 50% f the given amount disintegrates in 1600 years. What percentage of the substance disintegrates i 10 years ? (-log2)/(160)T a k ee=0. 9957

A radioactive substance disintegrates at as rate proportional to the amount of substance present. If 50% f the given amount disintegrates in 1600 years. What percentage of the substance disintegrates i 10 years ? (-log2)/(160)T a k ee=0. 9957

Experiments show that radium disintegrates at a rate proportional to the amount of radium present at the moment. It's half life is 1590 years. What percentage will disappear in one year? [Use e^(-log2/1590)=0. 9996 ]

Experiments show that radius disintegrates at a rate proportional to the amount of radium present at the moment.Its half life is 1590 years.What percentage will disappear in one year? [Use e^(-(log2)/(1500))=0.9996]

Experiments show that radius disintegrates at a rate proportional to the amount of radium present at the moment. Its half life is 1590 years. What percentage will disappear in one year? [Use e^(-log2/1590)=0. 9996 ]