If the ratio of the sum of n terms of two arithmetic progressions is `(3n+8):(7n+15)` then the ratio of their 12th terms is :

The sum of n terms of two arithmetic progressions are in the ratio (3n+8):(7n+15)* Find the ratio of their 12th terms.

The sum of n terms of two arithmetic progressions are in the ratio (3n+8):(7n+15)dot Find the ratio of their 12th terms.

The sum of n terms of two arithmetic progressions are in the ratio (3n+8):(7n+15)dot Find the ratio of their 12th terms.

The sum of n terms of two arithmetic progressions are in the ratio (3n+8):(7n+15). Find the ratio of their 12^th terms.

The sum of n terms of arithmetic progressions are in the ratio (3n+ 8): (7n+ 15). Find the ratio of their 12th terms.

IF the ratio between the sums of n terms of two arithmetic progressions is (7n+1): ( 4n+27), find the ratio of their 11th terms.

The sum of n terms of two arithmetic progressions are in the ratio 2n+3:6n+5, then the ratio of their 13th terms, is

The sum of n terms of two arithmetic progressions are in the ratio 2n+3:6n+5, then the ratio of their 13th terms, is

The ratio of the sum of n terms of two arithmetic progressions is given by (2n+3) : (5n -7) . Find the ratio of their nth terms.