In the titration of `1_2` (aq) by `S_2 O_3^(2-) (aq)` using the starch indicator, the end point is indicated by

Indicator used in the titration of Na_2 CO_3 and HCl is

Complete the chemical equations : MnO_4^(-) (aq) + S_2O_3^(2-)(aq) + H_2O (l) to

A mixture of acidified K_(2)Cr_(2)O_(7) and 10% Kl is titrated against against Na_(2)S_(2)O_(3) (sodium thiosulphate) solution using starch indicator. The colour of the reaction m ixture at the end point is:

I_(2(aq))+2S_(2)O_(3(aq))^(-2) to 2I_((aq))^(-)+S_(4)O_(6(aq))^(2-) For the above titrimetric reaction how is the end point determined?

Identify oxidant and reductant in the reaction : I_(2) ("aq") + 2S_(2) O_(3)^(2-) ("aq") 2I^(-) ("aq") + S_(4) O_(6)^(2-) (aq) .

Consider the reactions: 2S_2O_3^(2-) (aq) + I_2 (s) rarr S_4O_6^(2-) (aq) +2I^(-) (aq) S_2O_3^(2-)(aq) +2 Br_2 (I) harr 5H_2O (I) rarr 2SO_4^(2-) (aq)+ 4Br^(-) (aq) +10H^(+) (aq) Why does the same reductant, thiosulphate react differently with iodine and bromine ?

In the reaction : 2Al (s) + 6HCl(aq) to 2Al^(3+) (aq) + 6Cl^(-) (aq) + 3H_2O(g)