If y=f(x) passing through (1,2) satisfies are differential equation y(1+xy)dx-x dy=0, then

If a conic passes through (1, 0) and satisfies differential equation (1 + y^2) dx - xy dy = 0 . Then the foci is:

If the curve y=f(x) passing through the point (1,2) and satisfies the differential equation xdy+(y+x^(3)y^(2))dx=0 ,then

If a conic passes through (1, 0) and satisfies differential equation (1 + y^2) dx - xy dy = 0 . Then the equation of circle which is touching this conic at (sqrt(2),1) and passing through one of its foci is:

If the curve y=f(x) passes through the point (1, -1) and satisfies the differential equation : y(1+xy)dx=x dy , then f(- 1/2) is equal to :

If a curve y=f(x) passes through the point (1,-1) and satisfies the differential equation, y(1+x y)dx""=x""dy , then f(-1/2) is equal to:

If a curve y=f(x) passes through the point (1,-1) and satisfies the differential equation ,y(1+x y)dx""=x""dy , then f(-1/2) is equal to: