Factor `n^(2)-5n-14`.

Factorize 3n^(2)-108n+1023

(c) Factorize x^(2) -5x -14

In the followin electronic configuration, ns^(2)(n-1)d^(0-1)(n-2)f^(1-14) If value of (n-1)=5 the configuration will be of :-

Show that 2.6.10.14.. To n factors =(n+1)(n+2)(n+3) … to n factors.

Some of the factors of (n ^(2))/(2) + (n)/(2) are (1)/(2) ,n and (n+1). True or false.

On simplification factor of ""((5^(n+2)-6*5^(n+1))/(13*5^n-2*5^(n+1))) is

Show that 2.6.10……. to n factors =((2n)!)/(n!)

Write (2n)! =2n(2n-1)(2n-2) …3.2.1. Then combine the even factors and prove (2n)! =2^n.n!.[1.3.5...(2n-1)]

2+7+14+…..+ (n^(2) + 2n-1)=