Let A (1,3), B(0,0) and C(k,0) be the vertices of triangle ABC of area 3sq. Units find k using determinantd method.

Let A(1, 3), B(0, 0) and C(k, 0) be three points such that ar(triangle ABC) =3 sq units. Find the value of k.

Let A(0, 1, 1), B(3, 1, 5) and C(0, 3, 3) be the vertices of a triangle ABC . Using vectors, show that triangle ABC is right angled at C.

Select the correct options from the given alternatives.If A(0,0),B(1,3),C(k,0)are vertices of a triangle ABC whose area is 3sq.units then value of k is

Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three points in a plane. Area of the triangle ABC is (in sq. units)

Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three points in a plane. Area of the triangle ABC is (in sq. units)

A(0,0), B(6,0), C(4,3) and D(0,k) are the vertices of a quadrilateral ABCD .Find the value of k if the area of quadrilateral is 14 sq.units.

If area of the triangle with vertices (-2, 0), (0, 4) and (0, k) is 4 square units, find the value of 'k' using determinants.

Let A(a, 0), B(b, 2b +1) and C(0, b), b ne 0, |b| ne 1, be points such that the area of triangle ABC is 1 sq. unit, then the sum of all possible values of a is :

Find the value of k,if area of triangle is 4 sq. units and vertices arw (k,0),(4,0) and(0,2) using determinant.