Transverse wave is described by the equation `y=y_0 sin 2pi (ft-x/lambda)` .The maximum particle velocity is twice the wave velocity if wavelength is____

A transverse wave is described by the equation y=A sin [2pi(ft-x//lambda)] . The maximum particle velocity is equal the wave velocity if :

A transverse wave is described by the equation Y=Y_(0) sin 2 pi (ft-frac(x)(lambda) . The maximum particle velocity is four times the wave velocity if

A transverse wave is described by the equation y=A sin 2pi( nt- x//lambda_0) . The maximum particle velocity is equal to 3 times the wave velocity if

A transverse wave is described by the equation y=A sin 2pi( nt- x//lambda_0) . The maximum particle velocity is equal to 3 times the wave velocity if

A transverse wave is described by the equatiion Y = Y_(0) sin 2pi (ft -x//lambda) . The maximum particle velocity is equal to four times the wave velocity if lambda = pi Y_(0) //4 lambda = pi Y_(0)//2 lambda = pi Y_(0) lambda = 2pi Y_(0)

A transverse wave is described by the equation y= A sin 2 pi (vt - x/lambda) . The maximum particle velocity is equal to four times the wave velocity if

A transverse wave is derscried by the equation y=y_(0) sin 2 pi (ft - (x)/(lamda)) . The maximum particle velocity is equal to four times the wave velocity if :-

A transverse wave is derscried by the equation y=y_(0) sin 2 pi (ft - (x)/(lamda)) . The maximum particle velocity is equal to four times the wave velocity if :-