When light of wavelength `lambda` is incident on a metal surface, stopping potential is found to be x. When light of wavelength n`lambda` is incident on the same metal surface, stopping potential is found to be `(x)/(n+1)` . Find the threshold wavelength of the metal.

When light of wavelength λ is incident on a metal surface ,stopping potential is found to be V_circ . When light of wavelength nλ is in incident on the same metal surface ,stopping potential is found to be V_circ/(n+1) . The threshold wavelength of the metal is

When light of wavelength lambda is incident on photosensitive surface, the stopping potential is V. When light of wavelength 3lambda is incident on same surface, the stopping potential is V/6 Threshold wavelength for the surface is

When light of wavelength lambda is incident on photosensitive surface, the stopping potential is V. When light of wavelength 3lambda is incident on same surface, the stopping potential is V/6 Thereshould wave length for the surface is

When light of wavelength lambda is incident on photosensitive surface, the stopping potential is V. When light of wavelength 3lambda is incident on same surface, the stopping potential is V/6 Thereshould wave length for the surface is

When a photosensitive surface is illuminated with light of wavelength lambda , the stopping potential is V_(0) . But when light of wavelength 2lambda is incident on the same surface, the stopping potential is (V_(0))/(4) . What is the threshold wavelength for the surface ?