The refractive index of the core of an optical fibre is `mu_(2)` and that of the cladding is `mu_(1)` .The angle of incidence on the face of the core so that the light ray just under goes total internal reflection at the cladding is

The refractive index of the core of an optical fibre is mu_(2) and that ofth cladding is mu_(1) . The angle of incidence on the face of the core of that the light ray just under goes total internal reflection at the cladding is

Refractive index of cladding of optical fibre is ...... that of core of optical fibre.

If refractive index of core & cladding are mu_(1)&mu_(2) respectively then :

If refractive index of core & cladding are mu_(1) & mu_(2) respectively then :

At what angle should be a ray of light be incident on the face of a prism of refracting angle 60^@ so that it just suffers total internal reflection at the other face? (mu = 1.524) .

A light rays is incident on a prism of prism angle A and refractive index mu . Show that the smallest value of the angle of incidence for which the reflected ray does not suffer total internal reflection at the second face, i.e. just comes out of it, is given by i=sin^-1[(mu^2-1)^(1//2)sinA-cosA] .

In optical fibre is refractive index of core greater than cladding or smaller ?