The specific heat of ice at `0^(@)C` is

19 g of water at 30^@C and 5 g of ice at -20^@C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice =0.5calg^(-1) (.^(@)C)^(-1) and latent heat of fusion of ice =80calg^(-1)

19 g of water at 30^@C and 5 g of ice at -20^@C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice =0.5calg^(-1) (.^(@)C)^(-1) and latent heat of fusion of ice =80calg^(-1)

Specific heat of water at 20^@C is _______ and that of ice is _________

Ten grams of ice at - 20^(@)C is to be changed to steam at 130^(@)C . The specific heat of both ice and steam is 0.5 cal // ( g^(@)C) . The specific heat of water is 1.00 cal // ( g K ) . The heat of fusion is 80 cal // g and the heat of vaporization is 540 cal // g. The entire process requires.

Ice in a freezer is at –7^(@)C . 100 g of this ice is mixed with 200 g of water at 15°C. Take the freezing temperature of water to be 0°C, the specific heat of ice equal to 2.2 J//g .^(@)C , specific heat of water equal to 4.2 J//g .^(@)C , and the latent heat of ice equal to 335 J/g. Assuming no loss of heat to the environment, the mass of ice in the final mixture is closest to

In summer, Kamal decides to take a bath at noon. Temperature of the water in overhead tank is 45^(@)C so he decides to mix ince from refrigerator. The temperature of the ice in refrigerator. The temperature of the ice in refrigerator is -10^(@)C . How much ice will be needed to prepare 20 kg of water at 25^(@)C for bath? (Assume no loss to surrounding latent heat of fusion of ice =80cal//gm , specific heat of ice =0.5cal//gm^(@)C

In summer, Kamal decides to take a bath at noon. Temperature of the water in overhead tank is 45^(@)C so he decides to mix ince from refrigerator. The temperature of the ice in refrigerator. The temperature of the ice in refrigerator is 10^(@)C . How much ice will be needed to prepare 20 kg of water at 25^(@)C for bath? (Assume no loss to surrounding latent heat of fusion of ice =80cal//gm , specific heat of ice =0.5cal//gm^(@)C

10g of water at 30^(@)C and 5g of ice at -20^(@) C are mixed together in a calorimeter. What is the final temperature of the mixture? Given specific heat of ice= 0.5 cal g^(-1) (""^(0)C)^(-1) and latent heat of fusion of ice =80 cal g^(-1)

Find the amount of heat required to convert 10 kg ice at -10^(@)C to water at 50^(@)C . Given specific heat of ice 2100Jkg^(-1)K^(-1) , specific heat of water 4200Jkg^(-1)K^(-1) and latent heat of ice 3.36xx10^5Jkg^(-1)