In a series LR circuit, `X_L=R` and the power factor of the circuit is `P_1`.When a capacitor with capacitance C such that `X_C=X_L` is put in series , the power factor becomes `P_2`.Find out `P_1//P_2`.

In a series L_R circuit X_L = R and power factor of the circuit is P_1 . When capacitor with capacitance C such that X_L = X_C is put in series, the power factor becomes P_2 . Calculate P_1/P_2

ln a series LR circuit X_L = R and power factor of the circuit is P_1 . When capacitor with capacitance C such that X_L = X_C is p ut in series the power factor becomes P_2. Calculate P_1//P_2 .

In a series LR circuit X_(L) = R and power factor of the circuit is P_(1) . When capacitor which capacitance C such that X_(L) =X_(C) is put in series , the power factor becomes P_(2) .Calculate P_(1)//P_(2)

(i) An a.c. Source of voltage V = V_(0) " sin " omegat is connected to a series combination of L,C and R . Use the phasor diagram to obtain expression for impedance of the circuit and phase angle between voltage and current . Find the condition when current will be phase with the voltage . What is the circuit in this condition called ? (ii) In a series LR circuit X_(L) = R and power factor of the circuit is P_(1) . When capacitor which capacitance C such that X_(L) =X_(C) is put in series , the power factor becomes P_(2) .Calculate P_(1)//P_(2)

The power factor of L-R circuit is-

In a series resonant L-C-R circuit, the power factor is

In a series LCR circuit, V_L=V_C=V_R what is the value of power factor?