`tan^3x-3tanx=0`

tan^(3)x-3tanx=0

If tan of angles A,B,C are the solutions of the equations tan^3x+3ktan^2x-3tanx+k=0 , then the triangle ABC is

Evaluate: lim_(xto(pi)/(3))(tan^3x-3tanx)/(cos(x+(pi)/(6)))

If tanx+tan(x+pi/3)+tan(x+(2pi)/3)=3 then prove that (3tanx-tan^3x)/(1-3tan^2x)=1

Prove that tan 3x=(3tanx-tan^3x)/(1-3tan^2x)

If tan of the angles A , B , C are the solutions of the equations tan^(3)x-3ktan^(2)x-3tanx+k=0 , then the triangle ABC is

If the angles A , B , C are the solutions of the equations tan^(3)-3ktan^(2)x-3tanx+k=0 , then the triangle ABC is

tanx + tan2x + tan3x=0

Solve : tanx+tan2x+tan3x=0

lim_(xrarr0) (3 tan3x-4 tan2x-tanx)/(4x^(2)tanx)