If tangents are drawn from the origin to the curve ` y= sin x `, then their points of contact lie on-

Tangents are drawn from the origin to the curve y = sin x . Prove that their points of contact lie on the curve x^(2) y^(2) = (x^(2) - y^(2))

Tangents are drawn from the origin to the curve y = sin x . Prove that their points of contact lie on the curve x^2y^2=(x^2-y^2) .

Tangents are drawn from the origin to the curve y = sin x . Prove that their points of contact lie on the curve x^(2) y^(2) = (x^(2) - y^(2))

Tangents are drawn from origin to the curve y=sin+cos x Then their points of contact lie on the curve

Tangents are drawn from origin to the curve y = sin+cos x ·Then their points of contact lie on the curve

Tangents are drawn from origin to the curve y = sin+cos x ·Then their points of contact lie on the curve

Tangents are drawn from the origin to the curve y=cos X . Their points of contact lie on