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Calculate the change in entropy when 1 m...

Calculate the change in entropy when 1 mole nitrogen gas expands isothermally and reversibly from an initial volume of 1 litre to a final volume of 10 litre at `27^(@)C`

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Entropy is a measure of randomess of system. When a liquid is converted to the vapour state entropy of the system increases. Entropy in the phase transformation is calculated using Delta S = (Delta H)/(T) but in reversible adiabatic process Delta S will be zero. The rise in temperature in isobaric or isochoric process increases the randomness of system, which is given by Delta S = "2.303 n C log"((T_(2))/(T_(1))) C = C_(P) or C_(V) The change in entropy when 1 mole O_(2) gas expands isothermally and reversibly from an initial volume 1 litre to a final volume 100 litre at 27^(@)C

Entropy is a measure of randomess of system. When a liquid is converted to the vapour state entropy of the system increases. Entropy in the phase transformation is calculated using Delta S = (Delta H)/(T) but in reversible adiabatic process Delta S will be zero. The rise in temperature in isobaric or isochoric process increases the randomness of system, which is given by Delta S = "2.303 n C log"((T_(2))/(T_(1))) C = C_(P) or C_(V) The change in entropy when 1 mole O_(2) gas expands isothermally and reversibly from an initial volume 1 litre to a final volume 100 litre at 27^(@)C

What is the entropy change when 1 mole oxygen gas expands isothermally and reversibly from an initial volume of 10 L to 100 L at 300 K ?

What is the entropy change when 1 mole oxygen gas expands isothermally and reversibly from an initial volume of 10 L to 100 L at 300 K ?

6 moles of an ideal gas expand isothermally and reversibly from a volume of 1 litre to a volume of 10 litres at 27^(@)C . What is the maximum work done.

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