The position of a particel is expressed as ` vecr = ( 4t^(2)hati + 2thatj)` m. where t is time in second. Find the acceleration of the particle.

The position of a particle is expressed as vecr = ( 4t^(2)hati + 2thatj) m. where t is time in second. Find the acceleration of the particle.

The position of a particle is expressed as vecr = ( 4t^(2) hati + 2thatj) m, where t is time in second. Find the velocity o the particle at t = 3 s

The positione of a particle is expressed as vecr = ( 4t^(2) hati + 2thatj) m, where t is time in second. Find the velocity o the particle at t = 3 s

The position of a particle is given by vecr = 2t^(2) hati + 3t hatj + 4hatk where t is in second and the coefficients have proper units for vecr to be in metre. The veca(t) of the particle at t = 1 s is

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The acceleration of the particle is

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The acceleration of the particle is

The position of a particle is given by, vecr = (3.0t hati -2.0t^2 hatj + 4.0 hatk)m where t is in seconds and the coefficients have the proper units for r to be in metres. What is the magnitude and direction of velocity of the particle at t = 2.0 s ?

The position of a particle is given by vecr = 3t hati + 2t^(2) hatj + 5hatk , where t is in seconds and the coefficients have the proper units for vecr to be in metres. The direction of velocity of the particle at t = 1 s is

The position of a particle is given by vecr = 3t hati + 2t^(2) hatj + 5hatk , where t is in seconds and the coefficients have the proper units for vecr to be in meters. The direction of velocity of the particle at t = 1 s is