`underset(x to oo)lim sqrtx (sqrt(x+c)-sqrtx)=`

underset(xto oo)lim(sqrt(x-sqrtx)-sqrtx)

underset(x to oo)lim {sin sqrt(x+1)-sin sqrtx)=

underset(x to 0)lim 2 (sqrtx)=

underset(xto oo)lim(sqrt(x+sqrt(x+sqrtx))-sqrtx)

underset(x to oo)lim [sqrt(x+sqrt(x+sqrt(x)))-sqrtx]=

underset(x to 0)"Lt" sqrtx=

Prove that: underset(xrarrinfty)lim sqrtx (sqrt(x+3) - sqrtx)= 3/2

underset(xto 4)lim(sqrt(1+sqrt(2+sqrtx))-sqrt3)/(x-2)

If value of underset(x to a)lim (sqrt(a+2x)-sqrt(3x))/(sqrt(3a+x)-2sqrtx)" is equal to "(2sqrt3)/(m) , where m is equal to