Calculate rotational `K.E.` of earth about its own axis, taking it to be a sphere of mass `6 xx 10^(24) kg` and radius `6400 km`.

Calculate the moment of inertia of the earth about its diameter, taking it to be a sphere of 10^(25) kg and diameter 12800 km.

Calculate the moment of inertia of the earth about its diameter taking it to be a sphere of 10^(25)kg and diameter 12800 km

Calculate the angular momentum and rotational kinetic energy of the earth about its own axis. Given mass of the earth is 6 xx 10^(24) kg and its radius = 6.4 xx 10^3 km. [Moment of inertia of the earth about its axis of rotation is 2/5 mr^(2) ]

Calculate angular momentum of earth rotating about its axis. Take I = (2)/(5)MR^(2) , where M = 6 xx 10^(24) kg and R = 6400 Km .

Calculate the angular momentum of the earth rotating about its own axis. Mass of the earth = 5.98 xx 10^(27) kg, mean radius of the earth =6.37 xx 10^(6)m,M.I of the earth = (2)/(5)MR^(2) .

The earth circles the sun once a year. How much work would have to be done on the earth to bring it to rest relative to the sun, (ignore the rotation of earth about - its own axis) Given that mass of the earth is 6 × 10^(24) kg and distance between the sun and earth is 1.5 × 10^(8) km-

The earth circles the sun once a year. How much work would have to be done on the earth to bring it to rest relative to the sun, (ignore the rotation of earth about - its own axis) Given that mass of the earth is 6 × 10^(24) kg and distance between the sun and earth is 1.5 × 10^(8) km-