Assertion: The acceleration due to gravity on the moon is one-sixth that on the earth.
Reason : The law of gravitation is the same on both the moon and the earth.

Give reasons: Our mass is same on both the moon and the earth.

The acceleration due to gravity on the surface of the moon is one-sixth that on the earth. The radius of the moon is about one-fourth tha tof the earth. If v_(e) is the escape velocity on the surfaceo f the earth, then escape velocity on the surface of the moon will be

The acceleration due to gravity on the moon is one-sixth that on earth. If the average density of moon is three-fifth that of earth, the moon's radius in terms of earth's radius R_(e) is -

The acceleration due to gravity on the moon is one-sixth that on earth. If the average density of moon is three-fifth that of earth, the moon's radius in terms of earth's radius R_(e) is -

If acceleration due to gravity on the moon is one-sixth that on the earth, then the length and time period of seconds pendulum on the surface of moon are

The acceleration due to gravity on the moon is only one sixth that of earth.It the earth and moon are assume to have the same density, the ratio of the radii of moon and earth will be

The acceleration due to gravity on the moon is only one sixth that of earth.It the earth and moon are assume to have the same density, the ratio of the radii of moon and earth will be

If the acceleration due to gravity on the moon is one-sixth of that on the earth. What will be the change in length of a second pendulum there so that it may beat a second there? Take acceleration due to gravity on earth's surface =9.8 ?

If the acceleration due to gravity on the moon is one-sixth of that on the earth. What will be the change in length of a second pendulum there so that it may beat a second there ? Take acceleration due to gravity on earth surface =9.8 ms^(-2) .