9-3-:(1)/(3)+1=

The sum to infinity of the progression 9-3+1 -(1)/(3) + .... is

The sum of infinity of the progression 9-3+1-(1)/(3)+… is

The simplified of ((1)/(3)-:(1)/(3) xx(1)/(3))/((1)/(3)-:(1)/(3)"of"(1)/3)-(1)/(9) is

(4)/(9^((1)/(3))-3^((1)/(3))+1) is equivalent to :

(4)/(9^((1)/(3))-3^((1)/(3))+1) is equivalent to :

Find the sum of the following geometric series: (2)/(9)-(1)/(3)+(1)/(2)-(3)/(4)+rarr5 terms

Find the sum of the sequence (2)/(9), -(1)/(3), +(1)/(2), -(3)/(4)…… 5 - terms.

The following steps are involved in finding the value of 10 (1)/(3) xx 9(2)/(3) by using an appropriate indentity . Arrange them in sequential order . (A) (10)^(2) - ((1)/(3))^(2) = 100 - (1)/(9) (B) 10(1)/(3) xx 9(2)/(3) = (10 + (1)/(3)) (10 - (1)/(3)) (C) (10 + (1)/(3)) (10 - (1)/(3)) = (10)^(2) - ((1)/(3))^(2) [because (a + b) (a -b) = (a^(2) - b^(2))] (D) 100 - (1)/(9) = 99 + 1 - (1)/(9) = 99(8)/(9)

9,3,1,(1)/(3),(1)/(9),"…."

9,3,1,(1)/(3),(1)/(9),"…."