In a reaction vessel, 0.184 g of NaOH is required to be added for completing the reaction. How many millilitres of 0.150 M NaOH solution should be added for this reaction ?

In a reaction vessel 0.184 g of NaOH is required to be added for completing the reaction. How many millilitre of 0.150M NaOH solution should be added for this requirements?

In a reaction vessel 0.184 g of NaOH is required to be added for completing the reaction. How many millilitre of 0.150M NaOH solution should be added for this requirements?

In a reaction vessel 0.184 g of NaOH is required to be added for completing the reaction. How many millilitres of 0.150 M NaOH should be added for this requirement?

Using molarity as a conversion factor: An experiment calls for the addition to a reaction vessel of 0.200 g of sodium hydroxide (NaOH) in aqueous solution. How many milliliters of 0.200 M NaOH should be added? Strategy: According to equating 2.13 M=n_(solute)/V_(L) First we need to convert grams NaOH to moles NaOH , because molarity relates moles of solute to volume of solution. Then, we convert moles NaOH to litres of solution, using the molarity as a conversion factor. Here, 0.200 M means that 1 L of solution contains 0.200 moles of solute (NaOH) , so the conversion factor is: (1L soln)/(0.200 mol NaOH) (Converts mol NaOH to L soln)

Complete the reaction : Zn + 2NaOH to

Volume (in ml) 0f 0.7 M NaOH required for complete reaction with 350 ml of 0.3 M H_(3)PO_(3) solution is :

Volume (in ml) of 0.7 M NaOH required for complete reaction with 350 ml of o.3 M H_(3) PO_(3) solution is