If D is a Point on the side BC of a `Delta ABC` such that AD bisects `angleBAC`. Then

D is a point on the side BC of a DeltaABC such that AD bisects angle BAC . Then

D is a point on the side BC of a triangle ABC such that angleADC = angleBAC . Show that CA^2 = CB. CD.

D is a point on side BC of Delta ABC such that AD=AC. Show that AB>AD

D is a point on the side BC of a triangle ABC such that angleADC=angleBAC . Show CA^(2)=CB.CD

D is a point on the side BC of a triangle ABC such that angleADC=angleBAC .Show that CA^2=CB.CD .

Let O be the in-centre of a triangle ABC and D be a point on the side BC of Delta ABC , such that OD_|_BC If angle BOD=15^(@) , then angle ABC=?

D is the point on the side BC of ABC such that angleADC = angleBAC . Prove that, (BC)/(CA) = (CA)/(CD) .

D is a point on side BC of Delta ABC such that AD=AC (see Fig.7.47). Show that AB>AD

If D is mid point of the side BC of a triangle ABC and AD is perpendicular is AC then (a^(2) - c^(2))/b^(2) =

In figure , D and E are Points on side BC of a Delta ABC such that BD = CE and AD = AE . Show that Delta ABD cong Delta ACE.