`(cos(pi-x)cos(-x))/(sin(pi-x)cos(pi/2+x))=cot^(2)x`

Prove that: (cos(pi+x)cos(-x))/(sin(pi-x)cos(pi/2+x))=cot^2x

Prove the following: (cos(pi+x)cos(-x))/(sin (pi-x) cos(pi/2+x))=cot^2x

Prove that: (cos(pi+x)cos(-x))/(sin(pi-x)cos(pi/2+x)} =cot^2x

Prove that (cos(pi+x)cos(-x))/(sin(pi-x)cos(pi/2+x) = cot^2x

Prove the following: (frac(cos(pi+x)cos(pi-x))(sin(pi-x)cos(pi/2+x)))=cot^2x

(cos (pi+x).cos(-x))/(sin(pi-x).cos(pi/2+x)) = cot^2x

cos(2pi -x) cos (-x) - sin(2pi +x) sin (-x) = 0

(sin (pi + x) cos ((pi) / (2) + x) tan ((3 pi) / (2) -x) cot (2 pi-x)) / (sin (2 pi-x) cos (2 pi + x) csc (-x) sin ((3 pi) / (2) -x)) = 1

Prove that: cos((3pi)/2+x)cos(2pi+x)[cot((3pi)/2-x)+cot(2pi+x)]=1