For the function `f(x)=(x-1)(x-2)` defined on `[0,1/2]`, the value of 'c' satisfying Lagrange's mean value theorem is

For the function f(x) = (x-1) (x-2) difined on [0,(1)/(2)] , the value of c satisfying Lagrange's mean value theorem is

For the function f(x) = (x-1) ( x-2) ( x-3) in [0,4], value of 'c' in Lagrange's mean value theorem is

Let f(x)=e^(x), x in [0,1] , then the number c of Lagrange's mean value theorem is -

Let f(x) = e^(x), x in [0,1] , then a number c of the Lagrange's mean value theorem is

If f(x) = (x-1)(x-2) and a = 0, b = 4 , find 'c' using Lagrange's mean value theorem.

The value of ′c′ in Lagrange's mean value theorem for f(x) = x(x−2)^2 in [0,2] is-

The value of ′c′ in Lagrange's mean value theorem for f(x) = x(x−2)2 in [0,2] is-

The value of c of Lagrange's mean value theorem for f(x) = x(x-2)^(2) in [0,2] is