A body of mass 2 kg is thrown vertically upwards with K.E of 245 J. The acceleration due to gravity is `9.8 ms^(-2)`. The K.E. Of the body will become half at the height of

A body of mass 5kg is thrown up vertically with a kinetic energy of 1000J . If acceleration due to gravity is 10ms^(-2) , find the height at which the kinetic energy becomes half of the original value.

A body of mass 1 kg is thrown vertically upwards with initial K.E. of 98 joule. The height at which its energy is reduced to half will be

A body of mass 2 kg is thrown vertically with K.E. 490 J. Taking g=10 m//s^(2) . The height at which K.E. is reduced to half will be :

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity =9.8ms^(-2) )

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity =9.8ms^(-2) )

A body of mass 2 kg is projected vertically upward with a velocity of 2msec^(-1) . The K.E. of the body just before striking the ground is