Calculate the mass percentage of benzene `(C_6H_6)` and carbon tetrachloride `("CCI"_4)` if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.
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Mass of solution = Mass of benzene + Mass of carbon tetrachloride = 22 g + 122 g = 144g Mass percentage of benzene = Mass of benzene /Mass of solution x 100 `= (22g)/(144g) xx 100 = 15.28%` Mass percentage of `"CCl"_4 = ("mass of CCl"_4)/("mass of solution") xx 100 = 122/144 xx 100 = 84.72%`
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