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(a) 30 g of urea (M = 60 g "mol"^(-1)) i...

(a) 30 g of urea (M = 60 g `"mol"^(-1)`) is dissolved in 846 g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mmHg. (b) Write two differences between ideal solutions and non-ideal solutions.

Text Solution

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v.p. = 23.55 mm
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30 g of urea (M = 60 g "mol"^(-1) ) is dissolved in 846 g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mm Hg.

30 g of urea ( M = "60 g mol"^(-1) ) is dissolved in 846 g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mm Hg.

Knowledge Check

  • 6.0 g of urea (molecular weight = 60) was dissolved in 9.9 moles of water. If the vapour pressure of pure water is p_(0) , the vapour pressure of solution is

    A
    `0.10 p_(0)`
    B
    `1.10 p_(0)`
    C
    `0.90 p_(0)`
    D
    `0.99 p_(0)`

  • 6g of urea ( molecular weight =60) was dissolved in 9.9 moles of water. If the vapour pressure of pure water is P^(@) , the vapour pressure of solution is :

    A
    `0.10 P^(@)`
    B
    `1.10P^(@)`
    C
    `0.90P^(@)`
    D
    `0.99P^(@)`

  • 6.0 g of urea (molecules mass = 60)was dissolved in 9.9 moles of water. If the vspour presssure of pure water is P^(@) , the vapour pressure of solution is :

    A
    0.10 `P^(@)`
    B
    1.10 `P^(@)`
    C
    0.90 `P^(@)`
    D
    0.99 `P^(@)`

    • Similar Questions

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    30 g of urea (M=60g mol^(-1) ) is dissolved in 846g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mm Hg. (b) Write two differences between ideal solutions and non-ideal solutions,

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