Home
Class 12
CHEMISTRY
Why is K(a2) lt lt K(a1) for H2SO4 in wa...

Why is `K_(a_2) lt lt K_(a_1)` for `H_2SO_4` in water ?

Text Solution

Verified by Experts

`H_2SO_4` is a dibasic acid, it ionises in two stages and hence has two dissociation constants as given below :
(i) `H_2SO_4(aq) + H_2O (l) to H_3O^(+)(aq) + HSO_4^(-) (aq) , K_(a_1) gt 10`
(ii) `HSO_4^(-) (aq ) + H_2O (l) to H_3O^(+) (aq) + SO_4^(2-) (aq) , K_(a_2)= 1.2 xx 10^(-2)`
`K_(a_2) ` is less than `K_(a_1)` i.e., tendency to move towards the products is much less in (ii) than (i) . This is because the negatively charged `HSO_4^(-)` ion has much less tendency to donate a proton to `H_2O` as compared to neutral `H_2SO_4`.
Promotional Banner

Topper's Solved these Questions

  • THE P-BLOCK ELEMENTS

    U-LIKE SERIES|Exercise NCERT TEXTBOOK EXERCISES|42 Videos

  • THE P-BLOCK ELEMENTS

    U-LIKE SERIES|Exercise CASE BASED/ SOURCE-BASED INTEGRATED QUESTIONS|19 Videos

  • THE D-AND F-BLOCK ELEMENTS

    U-LIKE SERIES|Exercise SELF ASSESSMENT TEST (SECTION A ) MULTIPLE CHOICE QUESTIONS (CHOOSE THE CORRECT OPTION)|7 Videos

Similar Questions

Explore conceptually related problems

Why is K_(a_2)ltltK_(a_1) for H_2SO_4 in water?

Why is K_(a_(2)) ltlt K_(a_(1)) for H_(2) SO_(4) in water ?

A : For H_2CO_3 K_(a_1) lt K_(a_2) . R : H_2CO_3 is weaker acid than HCO_3^-

The pH of 0.1 M NaHCO_(3) is (Given K_(a1) and K_(a2) for H_(2)CO_(3) are 6.38 and 10.26 respectively. )

If osmotic pressure of 1M aqueous solution of H_(2)SO_(4) at 500K is 90.2 atm. Calculate K_(a2) of H_(2)SO_(4) . Give your answer after multiplying 1000 with K_(a2) . (Assuming ideal solution). (Given: K_(a1) of H_(2)SO_(4) is oo,R=0.082 l t-atm//mol-K) .

If osmotic presssure of 1M aqueous solution of H_(2)SO_(4) at 500 K is 90.2 atm. Calculate K_(a2) of H_(2)SO_(4) . Give your answer after multiplying 1000 with K_(a_(2)) . (Assumme ideal solution) [Given : K_(a_(1)) of H_(2)SO_(4)=oo ,R=0.082 L atm // mol-K]

Bromine in excess is dropped to a 0.01 M SO_(2) . All of SO_(2) is oxidized to H_(2)SO_(4) and the excess Br_(2) is removed by flushing with gaseous N_(2) . Determine the pH of the resulting solution assuming K_(a1) of H_(2)SO_(4) vary large & K_(a2) = 10^(-2) . Take the value of log (3.24) = 0.51 .

A reactant (A) forms two products A overset(K_(1)) to B , Activation energy E_(a1)A overset(K_(1)) to C , Activation energy E_(a2) If E_(a1) = 2E_(a2) , then K_(1) and K_(2) are related as