A body falling a vertically up with initial velocity 52 m/s from the ground passes twice a point at h height above at an interval of 10 s. The height h is `(g=10m//s^(2))`

An object thrown verticallly up from the ground passes the height 5 m twice in an interval of 10 s. What is its time of flight?

An object thrown verticallly up from the ground passes the height 5 m twice in an interval of 10 s. What is its time of flight?

A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower,It hits the ground after some time with a velocity of 80m/s .The height of the tower is : (g=10m/g^(2))

A body is rpojected vertically upwards with a velocity of 10m//s . If reaches the maximum height (h) in time (t). In time t//2 the height covered is (g= 10 m//s^@)

A body thrown vertically up from the ground passes the height of 102 m twice in an interval of 10 s. What was its initial velocity ?

A body thrown vertically up from the ground passes the height of 102 m twice in an interval of 10 s. What was its initial velocity ?

A body is projected vertically upwards with a velocity of 10m//s . It reaches the maximum vertical height in time t. What will be the height covered in time t/2 ?

A body dropped from a height h with initial velocity zero, strikes the ground with a velocity 3 m/s. Another body of same mass is thrown from the same height h with an initial velocity of 4 m/s. Find the final velocity of second mass, with which it strikes the ground.

balloon is rising vertically up with a velocity of 29 m/s. A stone is dropped from it and it reaches the ground in 10 seconds. The height of the balloon when the stone was dropped from it is (g = 9.8 m/s^2)