Two `U-`tube manometers are connected to a same tube as shown in figure. Datermine difference of pressure between `X` and `Y`. Take specific gravity of mercury as `13.6. (g = 10 m//s^(2), rho_(Hg) = 13600 kg//m^(3))`

Pressure 3 m below the free surface of a liquid is 15KN//m^(2) in excess of atmosphere pressure. Datermine its density and specific gravity. [g = 10m//sec^(2)]

The column of mercury in a barometer is 76mm of Hg. Calculate the atmospheric pressure if the density of mercury = 13600kgm −3 . (Take g=10ms −2 )

A liquid of specific gravity 0.8 rises up in a capillary tube up to a height of 10 cm, while mercury falls down by 4 cm in the same tube. If the angle of contact between surface of the tube and liquid is zero and it is 135^(@) for mercury, calculate the ratio of surface tension of mercury and the liquid. Take, specific gravity of mercury =13.6 cos 135^@=-0.71

The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm. Calculate this pressure in SI and CGS units the following data, Specific gravity of mercury = 13.6, Density of water = 10^3 kg/m^3, g=9.8 m/s^2 at Calcutta. Pressure =h rho g in usual symbols.

The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm. Calculate this pressure in SI and CGS units the following data, Specific gravity of mercury = 13.6, Density of water = 10^3 kg/m^3, g=9.8 m/s^2 at Calcutta. Pressure =h rho g in usual symbols.

The height of mercury column in a barometer in a Calcutta laboratory was recorded to be 75 cm. Calculate this pressure in SI and CGS units the following data, Specific gravity of mercury = 13.6, Density of water = 10^3 kg/m^3, g=9.8 m/s^2 at Calcutta. Pressure =h rho g in usual symbols.