A radioactive with half life `T=693.1` days. Emits `beta`-particles of average kinetic energy `E=8.4xx10^(-14)` joule. This radionuclide is used as source in a machine which generates electrical energy with efficiency `eta=12.6%`. Number of moles of the nuclide required to generate electrical energy at an initial rate is `P=441 KW`, is `nxx10^(n)` then find out value of `(n)/(m) (log_(e )2=0.6931)N_(A)=6.023xx10^(23)`

A radio nuclide with half-life T days emits beta -particles of average kinetic energy E J . The radionuclide is used as a source in a machine which generates electric energy with efficiency 25% . The number of moles of the nuclide required to generate electrical energy at an initial rate P is n=(yTP)/(EN ln(2)) where 'y' is

A radio nuclide with half life T = 69.31 second emits beta -particles of average kinetic energy E = 11.25eV . At an instant concentration of beta -particles at distance, r = 2m from nuclide is n = 3 xx 10^(13) per m^(3) . (i) Calculate number of nuclei in the nuclide at that instant. (ii) If a small circular plate is placed at distance r from nuclide such that beta -particles strike the plate normally and come to rest, calculate pressure experienced by the plate due to collision of beta -particle. (Mass of beta -particle = 9 xx 10^(-31)kg ) (log_(e) 2 = 0.693)

Polonium ( _84^210 Po ) emits _2^4He particles and is converted into lead ( _82^206Pb ). This reaction is used for producing electric power in a space mission. Po^210 has half-life of 138.6 days. Assuming an efficiency of 10% for the thermoelectric machine, how much ^210Po is required to produce 1.2xx10^7J of electric energy per day at the end of 693 days. Also find the initial activity of the material. Given : Masses of nuclei ^210Po=209.98264 amu, ^206Pb=205.97440 amu, _2^4He=4.00260 amu, 1 am u=931 MeV//c^2 and Avogadro's number = 6xx10^23//mol

The quantized energy of an electron in hydrogen atom for the n^(th) it level is given by E_n=(1.312)/n^2 xx 10^6 Jmol^(-1) , Calculate the energy required to remove the electron completely from an excited hydrogen atom when its quantized level, n=3 , (N_A=6.02 xx 10^(23) mol^(-1))

The average kinetic energy of one molecule of an ideal gas at 27^@C and 1 atm pressure is [Avogadro number N_A=6.023xx10^(23) ]

The average kinetic energy of one molecule of an ideal gas at 27^@C and 1 atm pressure is [Avogadro number N_A=6.023xx10^(23) ]