`2.5 xx 10^(-4)` M मेथैनोइक अम्ल की चालकता `5.25 xx 10^(-5)cm^(-1)` है इसकी मोलर चालकता और वियोजन मात्रा को परिकलित कीजिये। दिया गया है -
`Lambda^(0)_(H^(+)) = 349.5 Scm^(2) mol^(-1)`
`Lambda^(0)_(HCOO^(-)) = 50.5 S cm^(2) mol^(-1)`

Conductivity of 2.5 xx 10^(-4) M methonoic acid is 5.25 xx 10^(-5) S cm^(-1) . Calculate its molar Condcutivity and degree of dissociation. Given : lambda^(@) ( H^(+) = 349.5 S cm^(2) "mol"^(-1) and lambda^(@) ( HCOO^(-)) = 50.5 S cm^(2) "mol"^(-1) .

Conductivity of 2.5xx10^(-4) M methanoic acid is 5.25xx10^(-5)S com^(-1) . Calculate its molar conductivity and degree of dissociation. "Given ":lamda^(0)(H^(+))=349.5 S cm^(2) mol^(-1) and lamda^(0)(HCOO^(-))=50.5 S cm^(2) mol^(-1).

The conductivity of 0.001 "mol" L^(-1) solution of CH_(3)COOH " is " 3.905 xx 10^(-5) "S" cm^(-1) . Calculate its molar conductivity and degree of dissociation (alpha) . "Given" lambda^(@) (H^(+)) = 349.6 "S" cm^(2) "mol"^(-1) " and " lambda^(0) (CH_(3)COO^(-)) = 40.9 "S" cm^(2) "mol"^(-1) (b) Define electrochemical cell. What happens if external potential applied becomes greater than E_(cell)^(@) of electrochemical cell?