A `Bi^(210)` radionuclide decays via the chain
`Bi^(210)underset(lambda_1)rarr P_(0)underset(lambda_(2))rarrPb^(206)(stabl e)`
where the decay constants are `lambda_(1)=1.60.10^(-6)s^(-1), lambda_(2)= 5.80.10^(8)s^(-1)`. Calculate alpa-disintegrations and four `beta-` disintegrations ?

A Bi^(210) radionuclide decays via the chain Bi^(210)(beta^(-)-"decay")/(lambda_(1))Po^(210)(alpha-decay)/(lambda_(2)) Pb^(206) (stable), where the decay constants are lambda_(1) = 1.6 xx 10^(-6)s^(-1), T_(1//2) ~~ 5 days , lambda_(2) = = 5.8 xx 10^(-8)s^(-1), T_(1//2) ~~ 4.6 months. alpha & beta activites of the 1.00 mg a month after its manufacture is (x)/(5) xx 10^(11) Find x.2^((1)/(4.6)) = 0.86

The average (mean) life of a radio nuclide which decays by parallel path is Aoverset(lambda_(1))(rarr)B : lambda_(1)=1.8xx10^(-2)sec^(-1) 2Aoverset(lambda_(2))(rarr)B , lambda_(2)=10^(-3)sec^(-1)

A radioactive nuclide can decay simultaneously by two different processes which have decay constants lambda_(1) and lambda_(2) . The effective decay constant of the nuclides is lambda .

The wavelength of two sine waves are lambda_(1) = 1 m and lambda_(2) = 6 m . Calculate the corresponding wave numbers .

A sample of ._(19)K^(40) disintegrates into two nuclei Ca & Ar with decay constant lambda _(Ca)=4.5 xx10^(-10) S^(-1) and lambda_(Ar)=0.5xx 10^(-10)S^(-1) respectively. The time after which 99% of ._(19)K^(40) gets decayed is