Home
Class 12
PHYSICS
A point source of electromagnetic radiat...

A point source of electromagnetic radiation has an average power output of `1500W`. The maximum value of electric field at a distance `3m` from this source in `Vm^-1` is

A

500

B

100

C

`(500)/(3)`

D

`(250)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
Average intensity of electromagnetic waves is
`I = (P)/( 4pi r ^(2)) = 1/2 epsi _(0) E _(0) ^(2) c or E _(0) [ (P)/( 2pi r ^(2) epsi _(0) x )] ^(1//2) `
Substituting the given vlaues, we get
`E _() [ (1500 )/( 2pi ( 3 ) ^(2) xx [ (1 //4pi xx 9 xx 10 ^(9)) ] xx 3 xx 10 ^(8))]^(1//2)`
`= 100 V m ^(-1)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC WAVES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3 : ONE OR MORE THAN ONE OPTION CORRECT TYPE)|10 Videos

  • ELECTROMAGNETIC WAVES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3 : ONE OR MORE THAN ONE OPTION CORRECT TYPE)|10 Videos

  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENT

    MTG-WBJEE|Exercise WB JEE Previous Years Questions |14 Videos

  • ELECTROSTATICS

    MTG-WBJEE|Exercise (WB JEE Previous Years Questions ) CATEGORY 3 : One or More than One Opion correct Type|4 Videos

Similar Questions

Explore conceptually related problems

A point source of electromagnetic radiation has an average power output of1500W. The maximum value of electric field at a distance 3m from this source in Vm^-1 is

A point source of electromagnetic radiation has an average power output of 800 W . The maximum value of elecvtric field at a distance 4.0 m from the source is

A point source of electromagnetic radiation has an average power output of 800W. The mximum value of electric field at a distance 3.5 m from the source will be 62.6 V/m, the maximum value of magnetic field will be -

A point source of electromagnetic radiation has an average power output of 800W . The maximum value of electric field at a distance 3.5m from the source will be 62.6 V/m , the energy density at a distance 3.5 m from the source will be- (in "joule"//m^(3) )

A point source, of electromagnetic radiation has average power output of 800 W. The maximum value electric at a distance 4.0 m from the source is:

A point source of electromagnetic radiation has an average power output of 800W. (a) Find the maximum value of electric field at a distance 3.5 m from the source. (b) What will be the maximum value of magnetic field? (c) What will be the energy density at a distance at a distance 3.5m from the source?

A point source of electromagnetic radiaction has average power output of 800 watt. Then find (a) Maximum value of electric field at a distance 3.5m from the source (b) Maximum vatue of magnetic field (c) Average energy density at 3.5 m from the source.

A point source of electromagnetic radiation has average power output of 800 watt, then find (a) Maximum value of electric field at a distance 3.5 m from the source (b) Maximum value of magnetic field (c) Average energy density at 3.5 m from the source.

A point source of 2 watt is radiating uniformly in all direction in vacuum. Find the amplitude of electric field at a distance 2m from it-

Power of a Source producing electromagnetic wave is 1500 W. Maximum value of electric field at a point 3m from the source is found to be E_0 measureed in V//m , E_0 // 20 = V//m