Home
Class 12
PHYSICS
A light beam travelling in the x-directi...

A light beam travelling in the x-direction is described by the electric field : `E_(y) = 270 "sin" omega(t-(x)/(c)).` An electron is constrained to move along the y-direction with a speed of `2.0xx10^(7) "ms"^(-1).` find the maximum electric force and maximum magnetic force on the electron.

A

`4.20 xx 10 ^(-15) N, 3.82 xx 10 ^(-16)N`

B

`3.62 xx 10 ^(-19) N, 1.63 xx 10 ^(-18) N`

C

`4.32 xx 10 ^(-17) N, 2.88 xx 10 ^(-18) N `

D

`5.31 xx 10 ^(-18) N, 5.62 xx 10 ^(-18) N`

Text Solution

Verified by Experts

The correct Answer is:
C
Maximum electric field, `E _(0) = 270 V m ^(-1) `
Maximum magnetic field,
`B _(0) = (E _(0))/(c) = ( 270 )/( 3 xx 10 ^(8)) = 9 xx 10 ^(-7) T,` directed alog z-direction.
Maximum electric force on the electron,
`F _(e) =q E_(0) =1. 6 xx 10 ^(-19) xx 270 = 4.32 xx 10 ^(-17) N`
Maximum magnetic force on the electron
`F_(m) = qvB_(0) = 1. 6 xx 10 ^(-19) xx 2.0 xx 10 ^(7) xx 9 xx 10 ^(-7) `
`= 2. 88 xx 10 ^(-18) N`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC WAVES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3 : ONE OR MORE THAN ONE OPTION CORRECT TYPE)|10 Videos

  • ELECTROMAGNETIC WAVES

    MTG-WBJEE|Exercise WB JEE WORKOUT (CATEGORY 3 : ONE OR MORE THAN ONE OPTION CORRECT TYPE)|10 Videos

  • ELECTROMAGNETIC INDUCTION AND ALTERNATING CURRENT

    MTG-WBJEE|Exercise WB JEE Previous Years Questions |14 Videos

  • ELECTROSTATICS

    MTG-WBJEE|Exercise (WB JEE Previous Years Questions ) CATEGORY 3 : One or More than One Opion correct Type|4 Videos

Similar Questions

Explore conceptually related problems

A light beam travelling in the x- direction is described by the electric field E_y(300V (m^-1) sin omega (t-(x//c)). An electron is constrained to move along the y-direction with a speed (2.0 xx (10^7) m (s^-1)). Find the maximum electric force and the maximum magnetic force on the electron.

A light beam travelling in the x -direction is described by the eectirc field E_(y) = (300 V//m) sin omega(t - x//c) . An electron is constrained to move along the y -direction with a speed of 2.0 xx 10^(7) m//sec . Find the maximum electric force and the maximum magnetic force on the electron.

A light beam traveling in the x-direction is described by th electric field E_(y)=300sin omega (t-x/c) . An electron is constarained to move along the y-direction with a speed of 2.0xx10^(7) m/s. Find the maximum electric force (in newton) on the electron.

The expression of electric field for a light beam travelling in the X- direction is E= 250 sin omega ( t - (x)/(c ) ) V//m A proton is travelling along the y-direction with a speed of 2.2 xx 10^7 m//s calculate the maximum electric force and maximum magnetic force on the electron .

A light beam is described by E = 800 sinOmega(t-x/c) . An electron is allowed to move normal to the propagation of light beam with a speed of 3xx10^7ms^(-1) . What is the maximum magnetic force exerted on the electron ?

Electromagnetic wave is travelling along X - axis and its electric field is found to oscillate along Y -axis amplitude 210 V/m what will be the amplitude of magnetic field ? One electron is constrained to move along Z- axis with a speed of 3xx 10^(-7) m/s . find maximum electric and magnetic force on electron .

A beam of light travelling aling x-axis is described by the magnetic field, B _(o) =5.2 xx 10 ^(-9) T sin omega (t - x//c). Then, (Charge on electron =1. 6 xx 10 ^(-19) C)

A beam of light travelling along x-axis is described by the magnetic field, E_y=(600 Vm^-1) sin omega (t-x//c) Calculating the maximum electric and magnetic forces on a charge q=2e, moving along y-axis with a speed of 3xx10^7m//s , where e=1.6xx10^(-19)C .

A beam of light travelling along x-axis is described by the magnetic field, B_z=5xx10^-9Tsin omega (t-x//c) Calculating the maximum electric and magnetic forces on a charge, i.e. alpha particle moving along y-axis with a speed of 3xx10^7m//s , charge on electron = 1.6xx10^-19C