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The points (5, -1,1)(7,4,7), (1, -6, 10)...

The points (5, -1,1)(7,4,7), (1, -6, 10) and (-1, -3, 4) are the vertices of a

A

trapezium

B

rhombus

C

rectangle

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine the type of quadrilateral formed by the points \( A(5, -1, 1) \), \( B(7, 4, 7) \), \( C(1, -6, 10) \), and \( D(-1, -3, 4) \), we will analyze the distances between the points and their direction ratios. ### Step 1: Calculate Direction Ratios First, we calculate the direction ratios for the line segments \( AB \), \( BC \), \( CD \), and \( DA \). 1. **Direction Ratio of \( AB \)**: \[ AB: (7 - 5, 4 - (-1), 7 - 1) = (2, 5, 6) \] 2. **Direction Ratio of \( BC \)**: \[ BC: (1 - 7, -6 - 4, 10 - 7) = (-6, -10, 3) \] 3. **Direction Ratio of \( CD \)**: \[ CD: (-1 - 1, -3 - (-6), 4 - 10) = (-2, 3, -6) \] 4. **Direction Ratio of \( DA \)**: \[ DA: (5 - (-1), -1 - (-3), 1 - 4) = (6, 2, -3) \] ### Step 2: Check for Parallelism Next, we check if any pairs of opposite sides are parallel by comparing their direction ratios. - **Comparing \( AB \) and \( CD \)**: \[ (2, 5, 6) \quad \text{and} \quad (-2, 3, -6) \] These are not scalar multiples, so \( AB \) is not parallel to \( CD \). - **Comparing \( BC \) and \( DA \)**: \[ (-6, -10, 3) \quad \text{and} \quad (6, 2, -3) \] These are also not scalar multiples, so \( BC \) is not parallel to \( DA \). ### Step 3: Calculate Distances Now we calculate the lengths of all sides using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] 1. **Distance \( AB \)**: \[ AB = \sqrt{(7 - 5)^2 + (4 - (-1))^2 + (7 - 1)^2} = \sqrt{2^2 + 5^2 + 6^2} = \sqrt{4 + 25 + 36} = \sqrt{65} \] 2. **Distance \( BC \)**: \[ BC = \sqrt{(1 - 7)^2 + (-6 - 4)^2 + (10 - 7)^2} = \sqrt{(-6)^2 + (-10)^2 + 3^2} = \sqrt{36 + 100 + 9} = \sqrt{145} \] 3. **Distance \( CD \)**: \[ CD = \sqrt{(-1 - 1)^2 + (-3 - (-6))^2 + (4 - 10)^2} = \sqrt{(-2)^2 + 3^2 + (-6)^2} = \sqrt{4 + 9 + 36} = \sqrt{49} = 7 \] 4. **Distance \( DA \)**: \[ DA = \sqrt{(5 - (-1))^2 + (-1 - (-3))^2 + (1 - 4)^2} = \sqrt{(6)^2 + (2)^2 + (-3)^2} = \sqrt{36 + 4 + 9} = \sqrt{49} = 7 \] ### Step 4: Analyze the Results From the calculations: - \( AB = \sqrt{65} \) - \( BC = \sqrt{145} \) - \( CD = 7 \) - \( DA = 7 \) Since \( AB \) and \( BC \) are not equal to \( CD \) and \( DA \), the quadrilateral does not have equal opposite sides, ruling out a rectangle or rhombus. ### Conclusion Since neither pairs of opposite sides are parallel nor are all sides equal, the quadrilateral formed by the points \( A, B, C, D \) is not a trapezium, rhombus, rectangle, or any standard quadrilateral. Therefore, the answer is **none of these options**.
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