To what series does the spectral line of atomic hydrogen belong if its wave number is equal to the difference between the wave numbers of the following two lines of the Balmer series: `486.1`and `410.2nm`? What is the wavelength of that time?

To what series does the spectral lines of atomic hydrogen belong if its wavenumber is equal to the difference between the wavenumber of the following two lines of the Balmer series 486.1 and 419.2 nm ? What is the wavelength of that line ?

To what series does the speciral lines of atomic hydrogen belong if its wavelength is equal to the difference between the wavenumber of the folowing two lines of the Balmer series 486.1 and 419.2 nm ? What is the waveeath of thqat line ?

The wave number of the first line in the balmer series of Be^(3+) ?

The wave number of the first line in the balmer series of Be^(3+) ?

write the formula for the wave number of a spectral line of Balmer series.

The difference between the wave number of 1st line of Balmer series and last line of Paschen series for Li^(2+) ion is :

The difference between the wave number of 1st line of Balmer series and last line of Paschen series for Li^(2+) ion is :

The emission spectrum of hydrogen atoms has two has two lines of Balmer series with wavelength 4102Å and 4861Å . To what series does a spectral line belong if its wave nmnber is equal to the difference of wave number is of above two lines ? What is the wavelength of this line? [TakeR=1.097xx10^(7)m^(-1)]

The wave number of limiting line in Balmer series of hydrogen atoms is

The wave number of the shortest wavelength transition in the Balmer series of H atom is