The value of `int_0^(3pi/2)cos^4 3x*sin^2 6x dx` equals

The value of int_(0)^((pi)/(6)) cos ^(3) 3x dx

The value of int_(0)^(2 pi)(sin^(2)x-cos^(4)x)dx is equal to pi/k then k

The value of int_(0)^(pi) e^(sin^(2)x) cos^(3)x dx is equal to -

The value of int_(-pi)^(pi) sin^(3) x cos^(2) x dx is equal to

Find the value of int_0^(pi/2)sin^4x/(sin^4x+cos^4x)dx

If f(x) = |(sin x + sin 2x + sin 3x, sin 2x , sin 3x),(3 + 4 sin x, 3, 4 sin x),(1 + sin x, sin x, 1)| then the value of int_0^(-pi//2) f(x) dx equals :

The value of int_(pi/4)^((3pi)/4)(cos x)/(1-cos x)dx is equal to (k-(pi)/(2)) then k=

The value of int_0^(pi//2) log ((4+3 sin x)/(4+3 cos x)) dx is:

The value of the integral int_(0)^(pi/2)(cos x)/((2+sin x)(4+sin x))dx equals