" (20) Let the sum of "n,2n,3n" terms of an A.P.be "S_(1),S_(2)" and "S_(3)" respectively Show that "S_(3)=3(S_(2-)S_(1))

Let the sum of n,2n,3n terms of an A.P.be S_(1),S_(2) and respectively,show that S_(3)=3(S_(2)-S_(1))

The sum of n,2n,3n terms of an A.P.are S_(1),S_(2),S_(3) respectively.Prove that S_(3)=3(S_(2)-S_(1))

If the sum of n, 2n, 3n terms of an A.P are S_(1), S_(2), S_(3) , respectively, prove that S_(3) = 3 (S_(2) -S_(1)).

The sums of n, 2n , 3n terms of an A.P. are S_(1) , S_(2) , S_(3) respectively. Prove that : S_(3) = 3 (S_(2) - S_(1) )

The sum of n,2n,3n terms of an A.P.are S_(1)S_(2),S_(3), respectively.Prove that S_(3)=3(S_(2)-S_(1))

If the sum of n,2n,3n terms of an AP are S_(1),S_(2),S_(3) respectively.Prove that S_(3)=3(S_(2)-S_(1))

If the sum of first n,2n,3n terms of an A.P. be S_1 , S_2 and S_3 respectively then prove that S_3=3(S_2-S_1)

Let sum of n , 2n , 3n , terms of an A.P are S_(1), S_(2), S_(3) respectively. Prove that S_(3) = 3 (S_(2) - S_(1)) .

If the sums of n, 2n and 3n terms of an A.P. be S_(1), S_(2), S_(3) respectively, then show that, S_(3) = 3(S_(2) - S_(1)) .