A particle of mass `m` attached to a string of length `l` is descending circular motion on a smooth plane inclined at an angle `alpha` with the horizontal. For the particle to reach the highest point its velocity at the lowest point should exceed.

In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point is

In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point is

A particle of mass m is attached to a string of length L and given velocity sqrt(10gL) in the horizontal direction at the lowest point. Find tension in the string when the particle is at (i) lowest position (ii) highest position,

Particle A is relased form a point P on a smooth inclined plane inclined at an angle alpha with the horizontal. At the same instant another particle B is projected with initial velocity u making an angle beta with the horizontal .Both particle again on inclined plane. What is relation between alpha and beta .

If a particle of mass m is thrown with speed at an angle 60° with horizontal, then angular momentum of particle at highest point about point of projection is

If a particle of mass m is thrown with speed at an angle 60° with horizontal, then angular momentum of particle at highest point about point of projection is

Particle "A" is released from a point "P" on a smooth inclined plane inclined at an angle alpha with the horizontal.At the same instant another particle "B" is projected with initial velocity 'u' making an angle beta 'with the horizontal.Both the particles meet again on the inclined plane.the relation between ' alpha and beta is 1) alpha+beta=(pi)/(6) 2) alpha+beta=(pi)/(4) 3) alpha+beta=(pi)/(3) 4) alpha+beta=(pi)/(2)

A particle of mass m is tied to a light string of length l and rotated along a vertical circular path. What should be the minimum speed at the highest point of its path so that the string does not become slack at any position ?