The equation of directrix of a parabola is `3x + 4y + 15 = 0` and equation of tangent at vertex is `3x + 4y - 5 = 0`,Then the length of latus rectum is equal to

If the equation of latus rectum of a parabola is x+y-8=0 and the equation of the tangent at the vertex is x+y-12=0, then the length of the latus rectum is-

The equation of the latus rectum of a parabola is x+y=8 and the equation of the tangent at the vertex is x+y=12 .Then find the length of the latus rectum.

The equation of the latus rectum of a parabola is x+y=8 and the equation of the tangent at the vertex is x+y=12. Then find the length of the latus rectum.

The equation of the latus rectum of a parabola is x+y=8 and the equation of the tangent at the vertex is x+y=12. Then find the length of the latus rectum.

The equation of the latus rectum of a parabola is x+y=8 and the equation of the tangent at the vertex is x+y=12. Then find the length of the latus rectum.

The equation of the latus rectum of a parabola is x+y=8 and the equation of the tangent at the vertex is x+y=12. Then find the length of the latus rectum.

The equation of the axis and directrix of a parabola are y - 3 = 0 and x + 3 = 0 respectively and the length of the latus rectum is 8 units . Find the equation of the parabola and the coordinate of its vertex .

Consider the parabola whose focus is at (0,0) and tangent at vertex is x-y+1=0 The length of latus rectum is

Consider the parabola whose focus is at (0,0) and tangent at vertex is x-y+1=0 The length of latus rectum is