The time period of a simple pendulum of length 9.8 m is

The acceleration due to gravity at a place is pi^(2)m//s^(2) . Then, the time period of a simple pendulum of length 1 m is

The acceleration due to gravity at a place is pi^(2)m//s^(2) . Then, the time period of a simple pendulum of length 1 m is

A simple pendulum of length 25 cm has a time period of 1 s and another pendulum of length 100cm has a time period of 2s. The time period of a simple pendulum of length 125 cm will be

Calculate the period of a simple pendulum of length 0.98 m at a place where acceleration due to gravity is 9.8ms^(-2) .

Compare the time periods of two simple pendulums of length 1 m and 16 m at at place.

Find the expression of time period of a simple pendulum of length l.

The ratio of the time period of a simple pendulum of length l_(0) with a pendulum of infinite length is : (Where, R is the radius of earth)