Home
Class 11
PHYSICS
In a spring- mass system , the length of...

In a spring- mass system , the length of the spring is L, and it has a mass M attached to it and oscillates with an angular frequency `omega`. The spring is then cut into two parts, one (i) with relaxed length `alphaL` and the other (ii) with relaxed length `(1-alpha)` L. The force constants of the two spring A and B are

Promotional Banner

Similar Questions

Explore conceptually related problems

A spring has mass m suspended from it. What will happen to the frequency of oscillations if the spring is cut into two halves?

A spring has length'l' and spring constant 'k'. It is cut into two pieces of lengths l_(1) and l_(2) such that l_(1)=nl_(2) . The force constant of the spring of length l_(1) is

The length of a spring is L and it elongates through l when a load W is hung from its one end. Assume that the spring is cut into two equal parts and then the same load is hung from one end of any part of the divided spring calculate the increase in length of the spring now.

A spring having a spring constant k is loaded with a mass m. The spring is cut into two equal parts and one of these is loaded again with the same mass. The new spring constant i

If the system is suspended by the mass m the length of the spring is l_(1) . If it is inverted and hung by mass M, the length of the spring is l_(2) . Find the natural length of the spring.

A spring of constant K is cut into two parts of length in the ratio 2 : 3 . The spring constant of large spring is