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निम्न बारम्बारता बंटन के लिए बहुलक की गण...

निम्न बारम्बारता बंटन के लिए बहुलक की गणना कीजिए | ltबरgt `{:("वास्तु का आकार ",0-4,4-8,8-12,12-16,16-20,20-24,24-28,28-32,32-36,36-40 ),("बारम्बारता : "," "5," "7," "9," "17," "12," "10," "6," "3," "1," "0):}`

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{:("Class Interval",0-4,4-8,8-12,12-14,14-16,16-20,20-24,24-26,26-32,32-34,34-40,40-44,44-48),("Frequency"," "2," "4," "7," "5," "8," "3" "," "2," "1," "13," "5," "3," "3," "9):}

Draw a histogram to represent the following {:("Class interval ", 0-8,8-16,16-24,24-32,32-40),(" Frequency "," "6, " "9, " "12 , " "10, " "5):}

The range of the data 25, 18, 20, 22, 16, 6, 17, 12, 30, 32, 10, 19, 8, 11, 20 is

If A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 } , C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = {5, 10, 15, 20 } , find A – D

If A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 } , C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = {5, 10, 15, 20 } , find B – A

If A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 } , C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = {5, 10, 15, 20 } , find A – B

If A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 } , C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = {5, 10, 15, 20 } , find A – C

If A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 } , C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = {5, 10, 15, 20 } , find C – A

If A = {3, 6, 9, 12, 15, 18, 21}, B = { 4, 8, 12, 16, 20 } , C = { 2, 4, 6, 8, 10, 12, 14, 16 }, D = {5, 10, 15, 20 } , find B – C