[" The mass of "70%H_(2)SO_(4)" required for neutralisation of "1],[mol" of "NaOH" ."]

The mass of 70% H_(2)SO_(4) required for neutralization of one mole of NaOH is:

The mass of 70% H_(2)SO_(4) required for neutralization of one mole of NaOH is:

The mass of 80% pure H_(2)SO_(4) required to completely neutralise 60g of NaOH is

The mass of 60% HCl by mass required for the neutralisation of 10 L of 0*1 M NaOH is

Volume of 0.1M""H_(2)SO_(4) required to neutralize 30 mL of 0.2 N""NaOH is

Volume of 0.1M""H_(2)SO_(4) required to neutralize 30 mL of 0.2 N""NaOH is

The volume of 0.1M H_(2)SO_(4) required to neutralise completely 40mL of 0.2M NaOH solution is

Calculate the volume of 0.1 N H_(2)SO_(4) required to neutralise 200 ml. of 0.2 N NaOH solution. It is an acid base neutralisation reaction. Hence, at the neutralisation point. Number of equivalents of acid = Number of equivalents of base.