A=[[-1,1,2],[1,2,3],[3,1,1]]*(ag)/(c)dt

If A=[[1,1,2],[1,3,4],[1,-1,3]], B=adj(A) and C=3A then (|adj(B)|)/(|C|) is

If A=[[1,1,2],[1,3,4],[1,-1,3]], B=adj(A) and C=3A then (|adj(B)|)/(|C|) is

If A=[[1,2,3],[-1,0,2],[1,-3,1]], B=[[4,5,6],[-1,0,1],[2,1,2]], C=[[-1,-2,1],[-1,2,3],[-1,-2,2]] find A-2B+3C. Also verify that (A+B)+C=A+(B+C).

If A=[[1,2,3] , [-1,0,2] , [-2,-3,1]], B=[[4,5,1] , [-1,0,3] , [2,1,2]], C=[[-1,-2,1] , [-1,2,3] , [-1,-2,2]] then A-2B+3C=

If A=[[1,2,3],[-1,0,2],[1,-3,1]], B=[[4,5,6],[-1,0,1],[2,1,2]], C=[[-1,-2,1],[-1,2,3],[-1,-2,2]] find A-2B+3C

If A = [[1,-1,3] , [2,1,0] , [3,3,1]] then apply R_1 rarr R_2 and then C_1 rarr C_1 +2C_3 on A

If A [[1,2,0],[1,1,0],[-1,4,0]],B=[[1,2,3],[1,1,-1],[1,1,1]]"and"C=[[1,2,3],[1,1,-1],[2,2,2]] Show that AB=AC though B !=C .Verify that: A+(B+C)=(A+B)+C

If A=[(0,1,2),(1,2,3),(3,a,1)] and A^(-1)=[(1//2,-1//2,1//2),(-4,3,c),(5//2,-3//2,1//2)] , then the values of a and c are equal to

If A=[(0,1,2),(1,2,3),(3,a,1)] and A^(-10)=[(1//2,1//2,1//2),(-4,3,c),(5//2,-3//2,1//2)] , then the values of a and c are equal to

If A=[[1,2,3],[-1,0,2],[1,-3,1]], B=[[4,5,6],[-1,0,1],[2,1,2]] and C=[[-1,-2,1],[-1,2,3],[-1,-2,2]] verify that A+(B+C)=(A+B)+C