[4x-3y=11],[3x+7y=-1]

Find for what value of k the three straight lines 4x-3y=1 , 3x-4y+1=0 and kx-7y +3=0 are concurrent .

If [[3,-2],[-1,2]][[x],[y]]=[[11],[-5]] then 3x+7y=

The solution of the linear system of equation [[2,2,3],[7,1,1],[0,6,5]][[x],[y],[z]]=[[3y+11],[6z-1],[5y+11]]+[[x],[x],[4z]]+[[z],[3x],[4y]] has

" The solutions of the linear system of equations "[[2,2,3],[7,1,1],[0,6,5]][[x],[y],[z]]=[[3y+11],[6z-1],[5y+11]]+[[x],[x],[4z]]+[[z],[3x],[4y]],is

{:("Column A", 7x + 3y = 12","3x + 7y = 8 , "Column B"),(x-y,,1):}

Find the value of m for which the lines 4x -3y - 1 = 0, 3x - 4y + 1 = 0 and mx - 7y + 3 = 0 are concurrent.

The solutions of the linear system of [[2,2,2],[7,1,1],[0,6,5]][[x],[y],[z]]=[[3y+11],[6z-1],[5y+11]]+[[x],[x],[4z]]+[[z],[3x],[4y]] is

Find x and y,if [[2x+y,-1,1],[3,4y,4]]+[[-1,6,4],[3,0,3]]=[[3,5,5],[6,18,7]]

Find the value of (x-y) , if 3x+4y=11,4x+3y=10

Solve: x+2y+z=7 , x+3z=11 , 2x-3y=1