" A unit vector perpendicular to the lines "(x+1)/(3)=(y+2)/(1)=(z+1)/(2)" and "(x-2)/(1)=(y+2)/(2)=(z-3)/(3)" is "

The unit vector perpendiculat to the lines (x+1)/3=(y+2)/1=(z+1)/2"and"(x-2)/1=(y+2)/2=(z-3)/3 is

The lines (x)/(1)=(y)/(2)=(z)/(3) and (x-1)/(-2)=(y-2)/(-4)=(3-z)/(6) are

The lines (x)/(1)=(y)/(2)=(z)/(3)and(x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

The equation of the straight line passing through the origin and perpendicular to the lines (x+1)/(-3)=(y-2)/(2)=(z)/(1) and (x-1)/(1)=(y)/(-3)=(z+1)/(2) has the equation

cartesian equation of the line which is perpendicular to the lines (x)/(2)=(y)/(1)=(z)/(3) and (x-3)/(-1)=(y-2)/(3)=(z+5)/(5) and passes through the point (1,2,3)

The lines (x-2)/(1)=(y-3)/(2)=(z-4)/(3) and (x-1)/(-5)=(y-2)/(1)=(z-1)/(1) are

Find the vector and cartesian equation of the line passing through the point (2,1,3) and perpendicular to the lines. (x-1)/(1)=(y-2)/(2)=(z-3)/(3) and (x)/(-2)=(y)/(2)=(z)/(5)

Find the equation of the line passing through the point (-1,2,3) and perpendicular to the lines (x)/(2)=(y-1)/(-3)=(z+2)/(-2) and (x+3)/(-1)=(y+3)/(2)=(z-1)/(3)

What is the equation of the line passing through the point (1,2,3) and perpendicular to the lines (x+1)/(1)=(y+2)/(2)=(z+3)/(3) and (x)/(-3)=(y)/(2)=(z)/(5) ?