[int(x-sin x)/(1+cos x)dx=x tan((x)/(2))+p log|sec((x)/(2))|+c],[" then "p" is "]

int(x-sinx)/(1+cosx)dx= tan((x)/(2))+plog|sec((x)/(2))|+c rArr p=

int(log(1+cos x)-x tan((x)/(2)))dx

int(log(tan x))/(sin x cos x)dx=

int(1+tan x)/(x+ log sec x)dx =

int(1)/(sin x+sqrt(3)cos x)dx=(1)/(2)log tan((x)/(2)+(pi)/(3))+c

If int cos x log (tan""(x)/(2))dx = sin x log (tan""(x)/(2)) + f(x) then f(x) is equal to, (assuming c is a arbitrary real constant)

int(ln(1+sin^(2)x))/(cos^(2)x)dx

2. int(tan x)/(log sec x)dx

int (ln (tan x)) / (sin x cos x) dx