" (i) "root(5)(5x+2)=2

Find the value of x in each of the following . (i) root5(5x + 2) = 2 (ii) root3(3x - 2) =4 (iii) ((3)/(4))^(3)((4)/(3))^(-7)= ((3)/(4))^(2x) (iv) 5^(x-3) xx 3^(2x -8) = 225 (v) (3^(3x) . 3^(2x))/(3^(x)) = root4(3^(20))

If log_(x)((1)/(root(5)(2)))=(-1)/(5), then x=

If one root k(x-1)^(2)=5x-7 is double the other root, show that k = 2 or - 25.

If 2^(5x)-:2^(x)=root(5)(32). Then find the value of x

Solve the inequation : root(5)([3/(x+1)+7/(x+2)])lt root(5)(6/(x-1))

Solve the equation : root(5)([3/(x+1)+7/(x+2)])lt root(5)(6/(x-1))

y=2 is the root of y-3=2y-5x=8 is the root of (1)/(2)x+7=11

underset(x to 0)"Lt" (root5(2+x)-root5(2-x))/(sin hx)=