The function f and g are defined by `f(x)=6x+8, g(x)=(x-2)/(3)`.
Calculate the value of `gg(1)/(2)`

The function f and g are defined by f(x)=6x+8, g(x)=(x-2)/(3) . Write an expression for gf(x) in its simplest form.

The function f and g are defined as f(x) = 2x - 3 and g(x) = x + 3//2 . For what value of y is f(y) = g(y- 3) ?

f(x)=5x+3 g(x)=x^(2)-5x+2 The functions f and g are defined above. What is the value of f(10)-g(5) ?

If the functions of f and g are defined by f(x)=3x-4 and g(x)=2+3x then g^(-1)(f^(-1)(5))

If the functions of f and g are defined by f(x)=3x-4 and g(x)=2+3x then g^(-1)(f^(-1)(5))

If f: R to R and g: R to R are defined by f(x)=2x+3 and g(x)=x^(2)+7 , then the values of x such that g(f(x))=8 are

If f:R to R and g:R to R are defined by f(x)=(2x+3) and g(x)=x^(2)+7 , then the values of x such that g(f(x))=8 are

If two real functions f and g such that f(x)=x^(2) and g(x)=[x] , then the value of f(-2)+g(-1/2) is